Isn't the \lambda for the third harmonic \frac{2L}{3}?
If you use hookes law, don't we need to know the spring constant k before using this information to solve this problem?
Sorry to keep badgering you here, but I do not see how you get
\frac{1}{2}C^{-3/2}\int_{0}^{\infty}\sqrt{x} e^{-x}dx
The \sqrt{x} should be an x/C no? We let x = Cv², so that makes v² = x/C. The term you are substituting for there is v² not v. That would make the integral...
Oh ok, so you are saying that the original equation should be:
\int 4\pi\ (\frac{M}{2\pi RT})^{3/2} \cdot v^2 \cdot e^{\frac{-Mv^2}{2RT}} dv = 1
instead of:
\int 4\pi\ (\frac{M}{2\pi RT})^{3/2} \cdot v^2 \cdot e^{\frac{-Mv^2}{nRT}} dv = 1
?
Thanks for the reply, but I still seem to be a little lost. If I let C = \frac{M}{2RT} , that leaves me with 4 \pi \cdot ( \frac{C}{ \pi})^{3/2} \int \frac{x}{C} ... . I don't see how making the C = \frac{M}{2RT} helps me in the latter half of the integral because I have a n term in there...
Homework Statement
Given Maxwell's probability distribution function,
P(v) = 4\pi\ (\frac{M}{2\pi RT})^{3/2} \cdot v^2 \cdot e^{\frac{-Mv^2}{nRT}}
Where v = velocity, M = molar mass, R = Universal Gas Constant, n = # of mols, T = temperature, solve
\int P(v) dv =1 from 0 to...
Hi,
I have a question about the transfer of electrical charge from object to another. Basically, my professor stated that if you rub a rod with certain matierials, the rod will become charged. This is due to the convention that Ben Franklin came up with called the triboelectric series. So...
Homework Statement
A rod of length L carries a charge Q uniformly distributed along its length. The rod lies along the y-axis with one end at the origin. Find the potential as a function of position along the x-axis
Homework Equations
dV=\vec{E}\cdotp d\vec{l}
V=\frac{kq}{r}...
Oh my... so simple huh?! ^_^ Thank you. It looks like I calculated the radius of the Earth in meters when it should have been kilometers!! Thanks for seeing that for me.
Problem: Suppose that the Earth retained its present mass but was somehow compressed to half its present radius. What would be the value of g at the surface of this new, compact planet?
My work: So, this seems pretty simple, and I get the right answer, but I seem to be off by a lot of...
Actually, I did draw the FBD. It is just a little hard to show on the forum so I did not show it. But just so you believe me, here it is, or what I think it should be.
http://answerboard.cramster.com/answer-board/image/f82c0c65fe75d2ff30bd3844a0167c55.jpg [Broken]
Here is my work...
Hello, I have a question with a simple Tension - Mass problem. Here is the question:
For the systems in Equilibrium, find the unknown tensions and masses.
a) http://answerboard.cramster.com/answer-board/image/ed663c5fcb01e8fb6c7522cf963b49f1.jpg [Broken]
b)...
So that's it? Just do it mathmatically and it is fine? Awesome, I solved for the intersection time to be .6 hours and then plugged that back into my equation for Car A and got a distance of 4.8 km. Does that sound good?
Thank you for your help Bishop!!
Hello,
I am having an issue with this simple kinematics problem. I have the question visualized, well, at least I think I do. Here is the question:
Two cars are traveling along a straight road. Car A maintains a constand speed of 80 km/h; car B maintains a constant speed of 110 km/h...